Alternative for a for loop. How would I write this code without using a for loop?
显示 更早的评论
function approx = approxCosineFunction(x, t)
approx=1;
for i=1:1:t-1
addterm = (-1)^i*(x^(2*i))/factorial(2*i);
approx = approx + addterm;
end
end
2 个评论
Matt J
2017-11-2
There are already no for loops in the code that you've shown.
John Barber
2017-11-2
采纳的回答
James Tursa
2017-11-2
编辑：James Tursa
2017-11-2
To get the correct result, you need to make that divide an element-wise divide, and then add up the resulting terms into approx. E.g.,
addterm = (-1).^(1:1:t-1).*(x.^(2.*(1:1:t-1)))./factorial(2.*(1:1:t-1)); % <-- changed / to ./
approx = approx + sum(addterm); % <-- added the sum( )
But this will just give you the last approximation. If you wanted to return a vector containing all of the intermediate results as well, you could use cumsum instead. E.g.,
approx = approx + cumsum(addterm);
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