Plotting dirac delta function's spectrum

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geometry geometry
geometry geometry 2017-11-3
编辑： Marcos Duraes 2019-4-30
I used the following code to plot the spectrum of some functions. but it doesn't work for the function dirac(t-t0) at t0=0. How can I fix it?
syms t w;
syms g h U;
g(w)=fourier(dirac(t));
h=abs(g);
w=-10:.5:10.1;
U=angle(g);
figure;
plot(w, subs(h));
figure;
plot(w,subs(U));
  1 个评论
Marcos Duraes
Marcos Duraes 2019-4-30
编辑：Marcos Duraes 2019-4-30
%Para plotar a o gráfico de uma variable type syms utilize a função fplot(); Logo.
syms t w;
syms g h U;
g(w)=fourier(dirac(t));
h=abs(g);
U=angle(g);
figure;
fplot(g);

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采纳的回答

Star Strider
Star Strider 2017-11-3
The Fourier (and Laplace) transforms of the Dirac delta function are uniformly 1 for all omega (or ‘s’).
That is the result you get in ‘g(w)’.
  2 个评论
geometry geometry
geometry geometry 2017-11-3
Yes the Fourier transform of Dirac delta function equals one for all omega but the problem is that nothing is plotted when I run it.
Star Strider
Star Strider 2017-11-3
It does if you use fplot rather than plot:
syms t w g h U;
g(w)=fourier(dirac(t));
h=abs(g);
w=-10:.5:10.1;
U=angle(g);
figure;
fplot(g)
figure;
fplot(U)

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