Better solution than mod() while indexing

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Luke Heyerdahl
Luke Heyerdahl 2017-11-3
回答： Guillaume 2017-11-3
In this cutout, order is incremented each time through a loop, most likely more times than there are indexes in colors. Is there a better way to grab values in indexes in colors that avoids the if statement entirely?
ndx = (mod(order, length(colors));
if ndx = 0
ndx = length(colors);
end
color = colors(ndx));

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回答（1 个）

Guillaume
Guillaume 2017-11-3
Put the last colour first:
colors = [colors(end), colors(2:end-1)];
Then, simply mod and add 1:
color = colors(mod(ndx, numel(colors)) + 1);
If the loop just contains the code shown and the increment, then the loop can easily be eliminated. We would need to know how ndx is incremented though.

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