How to write a script for the following?

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Zhuoying Lin 2017-11-4

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https://ww2.mathworks.cn/matlabcentral/answers/365050-how-to-write-a-script-for-the-following

评论： Zhuoying Lin 2017-11-4

1 x 8 + 1 = 9
12 x 8 + 2 = 98
123 x 8 + 3 = 987
1234 x 8 + 4 = 9876
12345 x 8 + 5 = 98765
123456 x 8 + 6 = 987654
1234567 x 8 + 7 = 9876543
12345678 x 8 + 8 = 98765432
123456789 x 8 + 9 = 987654321

The script should iterate from 1 to 9 to produce the expressions on the left, then perform the specified operation to get the results on the right, and finally print exactly in the format above

Thank you!

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采纳的回答

Stephen23 2017-11-4

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https://ww2.mathworks.cn/matlabcentral/answers/365050-how-to-write-a-script-for-the-following#answer_289426

在 MATLAB Online 中打开

>> for k=1:9, n=sscanf(sprintf('%d',1:k),'%d'); fprintf('%d x 8 + %d = %d\n',n,k,n*8+k); end
1 x 8 + 1 = 9
12 x 8 + 2 = 98
123 x 8 + 3 = 987
1234 x 8 + 4 = 9876
12345 x 8 + 5 = 98765
123456 x 8 + 6 = 987654
1234567 x 8 + 7 = 9876543
12345678 x 8 + 8 = 98765432
123456789 x 8 + 9 = 987654321
>>

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Stephen23 2017-11-4

编辑：Stephen23 2017-11-4

在 MATLAB Online 中打开

@Zhuoying Lin: of course, there are always other ways of doing things. You could calculate n without any strings at all, which might even be more efficient:

n = sum((k:-1:1).*10.^(0:k-1));

e.g.

>> for k=1:9, n=sum((k:-1:1).*10.^(0:k-1)); fprintf('%d x 8 + %d = %d\n',n,k,n*8+k); end
1 x 8 + 1 = 9
12 x 8 + 2 = 98
123 x 8 + 3 = 987
1234 x 8 + 4 = 9876
12345 x 8 + 5 = 98765
123456 x 8 + 6 = 987654
1234567 x 8 + 7 = 9876543
12345678 x 8 + 8 = 98765432
123456789 x 8 + 9 = 987654321