Update axes position properly
显示 更早的评论
I have a GUI that has 2 options on the toolbarmenu. User may change the width of the axes or change the "template display", e.g. change the axes position. No problms if I change the width and then change the template display. But,if I change the template display first(initially I have: axes A, position 1; Axes B, position 2; Axes C, Position 3 - change to- axes A, position 3; Axes B, position 2; Axes C, Position 1) and then I change the width of the axes, the axes just deformat. I think the update of the position is not done properly. Can anyone help me? I have attached a piece of the code
采纳的回答
Robert
2017-11-6
When you create your three axes (titled A, B, and C) they appear from right to left across the figure and in reverse order (C, B, A) in the handle array allax. Therefore they appear in allax in right-to-left order. Your function assumes this when adjusting the widths of these axes. You wrote:
[~,B]= min(X);
set(allax(B),'Position',[Pos{B,1}(1), Pos{B,1}(2), NW, Pos{B,1}(4)]);
for i=1:num-1
set(allax(i),'Position',[Pos{i,1}(1)-(num-i)*(Pos{i,1}(3)-NW), Pos{i,1}(2), NW, Pos{i,1}(4)]);
end
which works before the axes order is changed. But when you reorder the axes on the figure, your expression for the position of each axes no longer behaves properly.
The good news: the fix is easy! You can get the order by sorting the x coordinates of the axes positions and use that to put them in the expected order in the for loop. Try replacing the lines above with:
[~, order] = sort(X); % allax(order) are in order from right to left
for i = 1:num
pos = Pos{order(i)};
% shift to the left by the difference in the old widths and the new
pos(1) = pos(1) - (i-1) * (pos(3) - NW);
% set new width
pos(3) = NW;
% apply changes
set(allax(order(i)), 'Position', pos);
end
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Graphics Object Properties 的更多信息
Translated by 
