Independent Function

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hamid
hamid 2012-4-26
Hello Everyone,
I am working on a project in which a values changes for every iteration, i want to make it independent.The code is this
for t1=-0.5:0.1:0.5
for t2=-0.5:0.1:0.5
w=w0.*exp(j*t2*x+j*t1*y);
end
end
In this code w0,x and y are 40*40 matrix, so whenever the loop started the value of w changes for every iteration. i want to save this w value for each iteration in 480*640 matrix. means for first iteration value will cover 1*1-1*40 index of a 480*640 matrix next iteration value has to cover 1*41-1*80 and so on.
This will eventually make a matrix of 480*640.
I am looking forward for a favorable response.
Thanks in advance Regards

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采纳的回答

Walter Roberson
Walter Roberson 2012-4-26
tvals = -0.5:0.1:0.5;
L = length(tvals);
w = cell(L,L);
for T1 = 1 : N
t1 = tvals(T1);
for T2 = 1 : N
t2 = tvals(T2);
w{T1, T2} = w0.*exp(j*t2*x+j*t1*y);
end
end
However, I do not understand how you intend to put this into a 640 x 480 matrix, as you are producing 11 * 11 (= 121) outputs and would need 16 * 12 (= 192) 40 x 40 outputs to fill a 640 x 480 matrix.

更多回答（2 个）

hamid
hamid 2012-4-26
thanks alot for the reply...i got your point..So how about taking values 0.7:0.1:0.8 (16) and 0.5:0.1:0.6 (12) values..Now what you say about this??
hamid
hamid 2012-4-26
I done some modifications like this..what you say?
tvals = -0.7:0.1:0.8;
L = length(tvals);
tvals1=-0.5:0.1:0.6;
L1=length(tvals1);
w = cell(L1,L);
for T1 = 1 : L1
t1 = tvals(T1);
for T2 = 1 : L
t2 = tvals(T2);
w{T1, T2} = w0.*exp(j*t2*x+j*t1*y);
end
end
  1 个评论
Jan
Jan 2012-4-26
Please use standard code formatting - see the "Markup help" link on this page.

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