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Direction of display of loop

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Raviteja
Raviteja 2011-3-21
t = linspace(0,2*pi);
x = cos(t)*sqrt(5);
y = sin(t)*sqrt(5/2);
plot(x,y)
The above code is generating a circle. I want to know the direction it is rotating. How can I do it in Matlab?

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采纳的回答

Andrew Newell
Andrew Newell 2011-3-21
How about this?
t = linspace(0,2*pi);
x = cos(t)*sqrt(5);
y = sin(t)*sqrt(5/2);
plot(x,y); hold on
quiver(x(1),y(1),x(2)-x(1),y(2)-y(1),10)

更多回答（2 个）

Doug Hull
Doug Hull 2011-3-21
t = linspace(0,2*pi);
x = cos(t)*sqrt(5);
y = sin(t)*sqrt(5/2);
comet(x,y)
  1 个评论
Raviteja
Raviteja 2011-3-21
I want to know the direction after the plot is completed.
I need direction in static plot.
Can you suggest me anything?

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Paulo Silva
Paulo Silva 2011-3-21
t = linspace(0,2*pi);
x = cos(t)*sqrt(5);
y = sin(t)*sqrt(5/2);
plot(x,y)
%text showing the location of 3 points
text(x(1),y(1),'\leftarrow 1')
text(x(10),y(10),'\leftarrow 10')
text(x(30),y(30),'\leftarrow 30')
%arrow showing the direction of the "loop"
if y(1)<y(10)
xlabel('it''s rotating counterclockwise')
text(x(1),y(1),'\uparrow','FontSize',18) %draw arrow
else
xlabel('it''s rotating clockwise')
text(x(1),y(1),'\downarrow','FontSize',18) %draw arrow
end
  3 个评论
显示 1更早的评论
Paulo Silva
Paulo Silva 2011-3-21
I updated the code, the part with the if statement does what you need?
Raviteja
Raviteja 2011-3-21
It is working! Thanks!

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