Direction of display of loop
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t = linspace(0,2*pi);
x = cos(t)*sqrt(5);
y = sin(t)*sqrt(5/2);
plot(x,y)
The above code is generating a circle. I want to know the direction it is rotating. How can I do it in Matlab?
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采纳的回答
Andrew Newell
2011-3-21
How about this?
t = linspace(0,2*pi);
x = cos(t)*sqrt(5);
y = sin(t)*sqrt(5/2);
plot(x,y); hold on
quiver(x(1),y(1),x(2)-x(1),y(2)-y(1),10)
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更多回答(2 个)
Paulo Silva
2011-3-21
t = linspace(0,2*pi);
x = cos(t)*sqrt(5);
y = sin(t)*sqrt(5/2);
plot(x,y)
%text showing the location of 3 points
text(x(1),y(1),'\leftarrow 1')
text(x(10),y(10),'\leftarrow 10')
text(x(30),y(30),'\leftarrow 30')
%arrow showing the direction of the "loop"
if y(1)<y(10)
xlabel('it''s rotating counterclockwise')
text(x(1),y(1),'\uparrow','FontSize',18) %draw arrow
else
xlabel('it''s rotating clockwise')
text(x(1),y(1),'\downarrow','FontSize',18) %draw arrow
end
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