0 个投票

Hi, my task would be to have a legend which is update dynamically as I loop over some data extracted from different files and I add them to a same plot, for instance. To put it better, I would like to "append" a label to my legend every time I update my plot. Would you know how to do it?
Chiara

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John Bailey
John Bailey 2018-5-12
编辑：John Bailey 2018-5-12
plot(Pss,'DisplayName','desired legend entry')
legend('-DynamicLegend')
Place that after your first plot and it will automically put the name of the plot variable into the legend.
Walter Roberson
Walter Roberson 2018-5-12
Note that dynamic legends did not exist at the time the original question was asked in 2011.
Matthew
Matthew 2018-9-25
Those were the days.
Moritz Stich
Moritz Stich 2022-3-31
Jon Bailey you are a dynamic legend. Thanks

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Paulo Silva
Paulo Silva 2011-3-21

1 个投票

clf
clc
hold all
x=0:0.01:2*pi;
b=zeros(5);
for a=1:5
b(a)=plot(x,sin(a*x));
legend(b(1:a))
pause(1) %just to see it being draw
end
Alternative with choosen names for each plot
clf
clc
hold all
x=0:0.01:2*pi;
b=zeros(5);
c={'one','two','three','four','five'};
for a=1:5
b(a)=plot(x,sin(a*x));
legend(b(1:a),c(1:a))
pause(1)
end

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Chiara Modenese
Chiara Modenese 2011-3-21
Thanks for a very helpful community. Question is answered.
Cheers. Chiara

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更多回答（2 个）

Matt Fig
Matt Fig 2011-3-21

0 个投票

How are you updating the plot? In a loop?
Chiara Modenese
Chiara Modenese 2011-3-21

0 个投票

Yes, in a simple loop. Data come from different structures, but this is not so important. Basically, I want to avoid this:
legend(ss(1).name,ss(2).name,ss(3).name);
where ss(i) are structures. Every time I run my code, I can chose the number of structures to create, so I do not want to modify my legend as a function of this but, instead, do it automatically (so if I have 5 structures, I expect 5 corresponding labels in my legend, no need to modify the code by hand).
Thanks, Chiara

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