Question about min and if function
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Dear All
I have a matrix of three column as below like the file provided, I would like to find the values from o or p columns which is the closest to q, I have written this code:
M=abs(o - q);
N=abs(p - q);
difference =[M N];
[~,ii] = min(difference,[],2);
if ii == 1
Result = o
else
Result = p
end
but it just return the p column to me, I am really confused about the results. I really appreciate your helps
Best Nima
3 个评论
Michal
2017-11-14
Add some test case data to your code and expected result.
if ii == 1
will only be true if all values of ii are equal to one, and by the way that you defined ii this is clearly not the case. That line does not operate element-wise on the elements of ii. You cannot use if to distinguish between different array values and cause different actions to happen without using a loop and indexing.
Even better would be to learn how to write vectorized code, in which case the loop is not required. These basic and important concepts for using MATLAB are explained in the Getting Started tutorials, which are highly recommended for all beginners:
What output do you expect to get?
采纳的回答
Oscar Briones
2017-11-14
hola trabajé un poco en tu pregunta y lo solucioné de la siguiente manera,
%%Import the data
datos=xlsread('test1.xls','Sheet1','A2:D12');
%%Create output variable
q = datos(:,1);
o = datos(:,3);
p = datos(:,4);
M = abs (o - q);
N = abs (p - q);
R=M>N
result=o.*(1-R)+p.*(R)
saludos desde chile
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