How to skip over zero values in an array?
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In an array of audio samples, I would like to copy non-zero samples to a different array, and skip over any zero samples. I have tried using a loop to traverse the array, but I am having issues with bounds.
arrayout = [];
% arraycount = 1;
dim = size(dialsound); % number of samples in audio sample I am using
c = 1;
while (c < dim(1,2))
while(dialsound(1,c) == 0)
c = c + 1;
end
arrayout(1,c) = dialsound(1,c);
c = c + 1;
end
采纳的回答
Akira Agata
2017-11-15
You can also do that by another way, like:
idx = abs(dialsound) < eps;
arrayout = dialsound(~idx);
2 个评论
Peter Kapteyn
2017-11-16
Akira Agata
2017-11-16
Thank you for your reply. To understand how this code works, I would recommend trying very simple example, like:
>> x = [1 2 0 2 1e-20]
x =
1.0000 2.0000 0 2.0000 0.0000
>> idx = x < eps
idx =
0 0 1 0 1
>> y = x(~idx)
y =
1 2 2
I hope it will be some help for your better understanding !
更多回答（1 个）
Matt J
2017-11-15
Is this what you want
arrayout=nonzeros(dialsound)
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