3D plot an ellipsoid?

6 次查看(过去 30 天)
hi, i'm making a code that will plot an ellipsoid with the following equations:
x = a * (cos*phi) * (cos * theta); y = b * (cos*phi) * (sin * theta); z = b * (sin*phi);
and i'm supposed to plot it with a = 2, and b = 1, but it doesn't appear to be working.. help anyone?
a = 2;
b = 1;
x = a * (cos*phi) * (cos * theta);
y = b * (cos*phi) * (sin * theta);
z = b * (sin*phi);
[Xm, Ym] = meshgrid(x,y);
surf(x,y,z)
  1 个评论
Rik
Rik 2017-11-16
phi and theta don't exist and you are using them as input to cos and sin.

请先登录,再进行评论。

采纳的回答

Akira Agata
Akira Agata 2017-11-17
How about using a fsurf function, like:
a = 2;
b = 1;
funx = @(theta,phi) a*cos(theta).*cos(phi);
funy = @(theta,phi) b*cos(theta).*sin(phi);
funz = @(theta,phi) b*sin(theta);
fsurf(funx,funy,funz,[-pi/2 pi/2 -pi pi])
  4 个评论
Akira Agata
Akira Agata 2019-5-29
How about using hgtransform ? The following is an example.
a = 2;
b = 1;
funx = @(theta,phi) a*cos(theta).*cos(phi);
funy = @(theta,phi) b*cos(theta).*sin(phi);
funz = @(theta,phi) b*sin(theta);
% Make rotation matrix (e.g Rotate pi/4 [rad] for y-axis)
M = makehgtform('yrotate',pi/4);
figure
h = fsurf(funx,funy,funz,[-pi/2 pi/2 -pi pi]);
daspect([1 1 1])
% Apply the rotation matrix
t = hgtransform('Parent',gca);
t.Matrix = M;
h.Parent = t;
example.png
DOMENICO GIOFFRE
DOMENICO GIOFFRE 2021-1-23
Hello. I have a 3x3 matrix describing a tilted ellypsoid. How can i plot this? Besides, is there a way to calculate the distance between its center and a point on the surface in the direction of x, y and z axes?
Thank you!
229.435 1.889 -5.708
1.889 207.544 4.372
-5.708 4.372 184.297
how can I rotate it 'back'

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Surface and Mesh Plots 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by