Plotting and returning handle to line?
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Hi there, i'm supposed to write a program that plots the function x(t) = cos(2*pi*t - theta) between the limits -1 > t > 1, and saves the handle of the resulting line. The angle theta is supposed to initially be 0 radians, and then, I need to re-plot line over and over with (theta = pi/10 rad), (theta = 2*pi/10 rad), (theta = 3*pi/10rad) and so forth up to (theta = 2*pi rad). I'm not sure how this is supposed to turn out, so this is what I have so far below. Can anyone help?
clc
clear all
for t_steps = 10 : 10 : 100
t = linspace(-1, 1, t_steps);
theta = 0; % or pi/10 or 2*pi
hlot = cos(2*pi*t - theta);
set(hlot, 'XData', t);
drawnow;
pause(1);
end
for t_steps = 10 : 10 : 100
t = linspace(-1, 1, t_steps)
theta = pi/10; % or pi/10 or 2*pi
xt = cos(2*pi*t - theta);
set(hlot, 'YDATA', t);
drawnow;
pause(1);
end
4 个评论
KALYAN ACHARJYA
2017-11-17
% Are you looking for this one, vary theta only
t=1:.1:10;
for n=0:100;
theta=n*pi/10;
hlot=cos(2*pi*t-theta);
plot(hlot);
hold on;
end
hold off;
Matt Amador
2017-11-17
KALYAN ACHARJYA
2017-11-17
编辑：KALYAN ACHARJYA
2017-11-17
I have given the answer as per your question, reduce the increase the step size in t, and check again. Pls, vote the answer.
t=1:.5:10; % .1 replace with .5
Matt Amador
2017-11-17
采纳的回答
KALYAN ACHARJYA
2017-11-17
clc;clear all;
t=1:.5:10; % reduce the steps, now more clear graphs visible
for n=0:100;
theta=n*pi/10;
hlot=cos(2*pi*t-theta);
plot(hlot);
hold on;
end
hold off;
% Is this are you looking for.
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