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Indexing for cell arrays

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Joseph Lee
Joseph Lee 2017-11-20
评论： Joseph Lee 2017-11-22
I have 10x1300 cell array z, how do i find a certain value of z using indexing
find(abs(z-z_position)<intvl) did not work
and how do i do the opposite as well? eg. z{1,1}(1)
A portion of z, z value is random for each cell.
Columns 1296 through 1300
[1×23 double] [1×23 double] [1×29 double] [1×23 double] [1×25 double]
[1×27 double] [1×25 double] [1×25 double] [1×25 double] [1×27 double]
[1×21 double] [1×25 double] [1×27 double] [1×27 double] [1×25 double]
[1×27 double] [1×29 double] [1×29 double] [1×25 double] [1×23 double]
[1×27 double] [1×25 double] [1×23 double] [1×27 double] [1×27 double]
[1×27 double] [1×27 double] [1×23 double] [1×21 double] [1×23 double]
[1×25 double] [1×29 double] [1×27 double] [1×27 double] [1×27 double]
[1×27 double] [1×21 double] [1×21 double] [1×29 double] [1×27 double]
[1×25 double] [1×25 double] [1×25 double] [1×21 double] [1×27 double]
[1×23 double] [1×25 double] [1×25 double] [1×25 double] [1×23 double]

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采纳的回答

Walter Roberson
Walter Roberson 2017-11-20
cellfun( @(Z) find(abs(Z-z_position)<intvl), z, 'uniform', 0)
the output will be a cell array each element of which is the list of indices for the corresponding cell in z.
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Walter Roberson
Walter Roberson 2017-11-21
Do you need to know just the value out of all of the M, or do you need to know which cell of M it came from and the index inside that cell?
Joseph Lee
Joseph Lee 2017-11-22
Only the min out of all the M, one single value.

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