Closest value between two vectors
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I have two vectors k and l.
k l
1 5
9 8
12 32
203 1003
… …
I want to find for each value in k, if the closest next value is in k or l (if its in k, add + 1 to a counter, if it’s l, add +1 to another counter. Any help would be imesnsly appreciated! Thanks a lot!
6 个评论
KL
2017-11-21
you want to compare every element in k with k and l? if so, the next element in k and the current element in l? for the above example of yours, what should be the output?
numnum
2017-11-21
KL
2017-11-21
I do not understand when you say ... closest value > is...
What does it mean?
...for k(2)= 9, closest value > is k(3)=12...
l(2) is 8, which is closer to 9 than 12.
and what happens to the last value of k? would you only compare it with l's last value (since there's no next element in k)?
numnum
2017-11-21
KL
2017-11-21
did you read my whole comment?
numnum
2017-11-21
回答(1 个)
Andrei Bobrov
2017-11-21
编辑:Andrei Bobrov
2017-11-21
kl =[1 5
9 8
12 32
203 1003];
z = randi([1 1003],8,1);
[~,ii] = min(abs(kl - reshape(z,1,1,[])),[],2);
out = accumarray(ii(:),1);
for numel(K) ~= numel(L):
K = randi([-45 120],12,1);
L = randi([-15 300],18,1);
z = randi([-45 300], 8 ,1);
[~,ii] = min(abs([K(:);L(:)] - z(:)'));
adds = accumarray((ii(:) > numel(K)) + 1,1);
3 个评论
numnum
2017-11-21
Image Analyst
2017-11-21
Then just create kl.
kl = [k, l];
If k and l are different lengths, then please say so. Also say WHY you are wanting to do this.
numnum
2017-11-21
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