Using a variable as both output and input and writing a condition in a function
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Hei , I have this function
function [lambda, lambdap,phip] = Palaeomagfun(I ,D,lambda,lambdax,phix )
lambda=atand(tand(I)/2) %in degree
lambdap=asind(sind(lambdax)*sind(lambda)+cosd(lambdax)*cosd(lambda)*cosd(D))
if sind(lambda)>=sind(lambdap)*sind(lambdax)
phip=phix+asind(cosd(lambda)*sin(D)/cosd(lambdap))
elseif sind(lambda)<sind(lambdap)*sind(lambdax)
phip=phix+asind(cosd(lambda)*sind(D)/cosd(lambdap))-180
end
and this script
Problem 2:
I=30
lambdax=47
phix=20
D=80
[lambda, lambdap,phip] = Palaeomagfun(I ,D,lambda,lambdax,phix )
*first,Is it possible to use lambda as an output and input at the same time or i need two function or something else?
second: is my if coding correct in the function?*
2 个评论
Adam
2017-11-21
In general, yes, it is possible to use the same variable as input and output, both in the function definition and in the function call, the two not being the same thing.
However, in your case passing in lamda is redundant anyway since you recalculate it straight away.
F.O
2017-11-21
采纳的回答
When you write
function [lamda, lambdap,phip] = Palaeomagfun(I ,lamda,lamdax,phix )
lamda=atand(tand(I)/2) %in degree
the input lamda you pass would be overwritten because of your first line inside the function.
How about using two variables, say lamda_in and lamda_out
function [lamda_out, lambdap,phip] = Palaeomagfun(I ,lamda_in,lamdax,phix )
8 个评论
F.O
2017-11-21
F.O
2017-11-21
KL
2017-11-21
but it doesint seem working
You have to provide more information! We cannot guess what do you are trying to do there.
When you write,
[lambda, lambdap,phip] = Palaeomagfun(I ,D,lambda,lambdax,phix )
all your variables you pass into your functions must be defined previously. As long as you don't do that you will get "undefined function or variable error".
Initialize that variable,try again and make sure you know what you are doing inside your function.
F.O
2017-11-21
KL
2017-11-21
Unfortunately it's still not very clear but if you want to calculate lambda based on I, write a function,
function lambda = findLambda(I)
your equation for lambda here
end
and then use this function return directly on your other function call,
[lambda, lambdap,phip] = Palaeomagfun(I ,D,findLambda(I),lambdax,phix )
I still do not understand your intention. But as Adam said, it is possible to have the same variable as input and output. But if reassign the input variable before using it's old value, it doesn't make any sense.
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