Why cannot I plot my pressure to my volume?

1 次查看（过去 30 天）
Christian Berwanger
Christian Berwanger 2017-11-21
评论： Walter Roberson 2017-11-21
Hello, I do have two tables (both 5001x1) One represents the pressure and one represents volume. Now I want to plot these. When I select both I cannot use the plots in the upper menu. When using it in the command windows
plot(pressure,volume)
gives me the error:
Too many arguments
What am I doing wrong here?
Thanks in advance

请先登录，再回答此问题。

回答（2 个）

Walter Roberson
Walter Roberson 2017-11-21
? You cannot pass table objects themselves to plot(); plot() is not defined on table objects.
But that would give you a different error. More likely you should check with
which -all plot
as you probably somehow have a different plot.m on your path.
  1 个评论
Christian Berwanger
Christian Berwanger 2017-11-21
which -all plot shows me just some matlab paths. None of these is an own function or variable.

请先登录，再进行评论。

Star Strider
Star Strider 2017-11-21
You most likely have a variable named ‘plot’.
Run this from a script or your Command Window:
which plot -all
If the first line is:
plot is a variable.
you have found the problem. (This is called ‘overshadowing’ a function.) The solution is to rename the variable to something that does not conflict with a function name.
  5 个评论
显示 3更早的评论
Star Strider
Star Strider 2017-11-21
You will need use the table2array function to convert them to double arrays, then plot them.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Lighting, Transparency, and Shading 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by