why won't this code run?

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LM
LM 2017-11-23
评论： LM 2017-11-23
[find(stock.permno)]==notrading(1);
for i=1:18522
end
for j=10137
newt=[find(toremove(i)==c)],:)=[];
end
for i=0:4
t((1+(i*126)):(126+(i*126)),:)=c((253+(i*378)):(379+(i*378)),:);
end
for i=1:5
trade(i).permno=top5(i,1);
for ii=0:4
trade(ii+1).price=d(1+(ii*252):252+(ii*252),4);
end

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采纳的回答

Bshara Murr
Bshara Murr 2017-11-23
编辑：Bshara Murr 2017-11-23
Probably because you used the same local variable inside the main and nested loop. Try replacing the second i by a j (in every instance you are referring to it), and end your "for" loops.

更多回答（1 个）

Walter Roberson
Walter Roberson 2017-11-23
You have
newt=[find(toremove(i)==c)],:)=[];
which attempts to do two assignments in one statement.
  3 个评论
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Walter Roberson
Walter Roberson 2017-11-23
Possibly you want
newt(find(toremove(i)==c),:)=[];
but it is difficult to be sure as your code does not mention newt anywhere else.
LM
LM 2017-11-23
got another error once i fixed it saying find has too many input arguments

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