convert structure class to double class

Question

ha ha 2017-11-23

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/368834-convert-structure-class-to-double-class

编辑： Stephen23 2017-11-23

Let's say:

A : 4x1 structure class
A= Field1 :[1000x1 double],
   Field2 : [2x1 double], 
   Field3 : [5x1 double],
   Field4 : [1x1 double]
A= Field1 : [1;2;3...;1000],
   Field2 : [99;11], 
   Field3 : [44;11;33;88;66],
   Field4 : [77]

Question: How can i convert "structure A" to "double class B" for the last third double ?

_Result_: B=[99;11;44;11;33;88;66;77]

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ha ha 2017-11-23

编辑：ha ha 2017-11-23

A is "structure class"

A is NOT "cell class".

Sorry.Plz see my edit

Birdman 2017-11-23

Check my answer.

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Answer 1

Stephen23 2017-11-23

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https://ww2.mathworks.cn/matlabcentral/answers/368834-convert-structure-class-to-double-class#answer_292803

编辑：Stephen23 2017-11-23

在 MATLAB Online 中打开

Fake data:

>> A.F1 = [1;2;3];
>> A.F2 = 4;
>> A.F3 = [5;6];
>> A.F4 = [7;8;9];

To concatenate all fields of a scalar structure you could convert to cell array using struct2cell as an intermediate step:

>> C = struct2cell(A);
>> cat(1,C{:})
ans =
   1
   2
   3
   4
   5
   6
   7
   8
   9

But most likely you would be much better off using a non-scalar structure, because then you can simply do this:

cat(1,A.field)

and also use simple-and-efficient indexing to access parts of the structure.

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Answer 2

Stephen23 2017-11-23

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/368834-convert-structure-class-to-double-class#answer_292796

编辑：Stephen23 2017-11-23

在 MATLAB Online 中打开

Using your example cell array:

>> A= {[99;11], [44;11;33;88;66], [77]};
>> cat(1,A{:})
ans =
                    99
                    11
                    44
                    11
                    33
                    88
                    66
                    77