I am facing error while executing this code,pls help me to solve this issue

2017 11 27
1 个回答
更新时间：2017 11 27
1 次查看（30 天）

0 个投票

A = [ 1 12 3 9 5
11 7 8 14 10
6 2 13 4 15]
C = zeros(size(A)) ;
[val,idx] = max(abs(A)) ;
for i = 1:size(A,3)
[val,idx] = max(abs(A(:,i)));
C(idx,i) = val
end

6 个评论
显示 4更早的评论 隐藏 4更早的评论

Prabha Kumaresan
Prabha Kumaresan 2017-11-27
if I run this code the value of idx is displayed as 2,but its not 2,and if i change the value of A to (5*10) or (4*15) the code was not getting executed.
Birdman
Birdman 2017-11-27
Ok,but what do you want to see for idx instead of 2?
Prabha Kumaresan
Prabha Kumaresan 2017-11-27
why idx is set to 2 even if i change the number of rows in A to 5 or 10
Prabha Kumaresan
Prabha Kumaresan 2017-11-27
ok A is 2D. if i change the number of rows in A to 5 or 10 in for loop the command i = 1:size(A,2) whether needs to get changed to i = 1:size(A,5) or i = 1:size(A,10)
KSSV
KSSV 2017-11-27
Irrespective of what is size of A..it should be size(A,2)...red about size command in matlab.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

KSSV
KSSV 2017-11-27

0 个投票

It should be run till size(A,2) not size(A,3)...note that your matrix A is 2D not 3D.

类别

在 帮助中心 和 File Exchange 中查找有关 Startup and Shutdown 的更多信息

标签

评论：

KSSV
KSSV
2017-11-27

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by