Generating the Ulam Spiral

2012 4 30
1 个回答
回答已采纳
11 次查看（30 天）

0 个投票

This short spiral(n) function is supposed to generate a number spiral centered at one. For the most part, I understand the code but I can't seem to grasp why the polynomial m^2-m+1 is used.
function S = spiral(n)
%SPIRAL SPIRAL(n) is an n-by-n matrix with elements
% 1:n^2 arranged in a rectangular spiral pattern.
S = [];
for m = 1:n
S = rot90(S,2);
S(m,m) = 0;
p = m^2-m+1;
v = (m-1:-1:0);
S(:,m) = p-v';
S(m,:) = p+v;
end
if mod(n,2)==1
S = rot90(S,2);
end
Any ideas?

请先登录，再回答此问题。

 采纳的回答

Prince
Prince 2012-4-30

0 个投票

Figured it out... the quadratic designates the values along the main diagonal.
For any future searchers

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Data Distribution Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by