I want to rewrite the following expression into arctan.

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safisay 2017-11-30

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https://ww2.mathworks.cn/matlabcentral/answers/370137-i-want-to-rewrite-the-following-expression-into-arctan

回答： Walter Roberson 2017-11-30

采纳的回答： Walter Roberson

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Hi All,

I want to rewrite the following expression into arctan. Can anyone help?

    m=(k_1*(sin(theta1) + cos(k_1*(gama - theta1))*sin(theta0) - cos(theta0)*sin(theta1) + cos(theta1)*sin(theta0) - M*sin(theta1) - k_1*sin(k_1*(gama - theta1)) - M*cos(k_1*(gama - theta1))*sin(theta1) + k_1*cos(theta0)*sin(k_1*(gama - theta1)) + M*k_1*sin(k_1*(gama - theta1)) - M*k_1*cos(theta1)*sin(k_1*(gama - theta1))))/(M*l*(2*k_1 - sin(k_1*(gama - theta1))*sin(theta1) + 2*k_1*cos(k_1*(gama - theta1))*cos(theta1) - k_1^2*sin(k_1*(gama - theta1))*sin(theta1))) - (k_1*(M*sin(theta1) - cos(k_1*(gama - theta1))*sin(theta1) - sin(theta0) + M*cos(k_1*(gama - theta1))*sin(theta1) - k_1*cos(theta1)*sin(k_1*(gama - theta1)) + cos(k_1*(gama - theta1))*cos(theta0)*sin(theta1) - cos(k_1*(gama - theta1))*cos(theta1)*sin(theta0) - M*k_1*sin(k_1*(gama - theta1)) + k_1*cos(theta0)*cos(theta1)*sin(k_1*(gama - theta1)) + k_1*sin(k_1*(gama - theta1))*sin(theta0)*sin(theta1) + M*k_1*cos(theta1)*sin(k_1*(gama - theta1))))/(M*(2*k_1 - sin(k_1*(gama - theta1))*sin(theta1) + 2*k_1*cos(k_1*(gama - theta1))*cos(theta1) - k_1^2*sin(k_1*(gama - theta1))*sin(theta1)))

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Answer 1

Walter Roberson 2017-11-30

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/370137-i-want-to-rewrite-the-following-expression-into-arctan#answer_293886

No, there are no log terms and no imaginary constants and no sqrt() of expressions; there is nothing to rewrite into arctan. It would make more sense to rewrite it into tan

Some of the trig calls can be combined, for whatever that is worth. That does not make it any easier to understand, and has nothing to do with rewriting to arctan.