for loops for two variables (not nested loop)

2017 11 30
2 个回答
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更新时间：2018 1 18
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I've a .dat file with 73280 length. i'm trying to find mean of first 100 values, then mean of 101 to 200 values, then 201 to 300 and so on until last 100 values. 1st error i got was "Index exceeds matrix dimensions." I rounded off the length to 73200 and got rid of this problem.
x = [];
y = rms (a1,100); %a1 is original data
b= length(y);
c= b/100;
for i =1:100:b
x= [mean(y(i:i+99))]
end
subplot (2,2,1); plot (t1, a1)
subplot (2,2,2); plot (x)
subplot (2,2,3); plot (t1,y)
the value of "x" is updating in every iteration. what i want is to store the every value of "x" and then plot it.

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UET Hussain
UET Hussain 2017-11-30
编辑：Stephen23 2017-11-30
when I try to apply another for loop,
x = [];
y = rms (a1, 100);
b= length(y);
c= b/100;
for i =1:100:b, j=1:c;
x= [mean(y(i:i+99))]
end
subplot (2,2,1); plot (t1, a1)
subplot (2,2,2); plot (x)
subplot (2,2,3); plot (t1,y)
it actually becomes nested loop, which i dont want

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Stephen23
Stephen23 2017-11-30

0 个投票

A loop is not required. Just use reshape. Then you can plot them all at one too!
>> N = 100;
>> V = rand(1,73280); % your data vector
>> Z = N*fix(numel(V)/N);
>> M = mean(reshape(V(1:Z),N,[]),1);
>> plot(M)

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UET Hussain
UET Hussain 2017-11-30
编辑：UET Hussain 2018-1-18
Hi Stephen...... thanks for reply... what if i dont know the size of a file (n above case "73280")????? actually i have over over 225 files hence cannot look at each file everytime i'm going to process it.

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更多回答（1 个）

M
M 2017-11-30

0 个投票

You can use
x=[x mean(y(i:i+99))];

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