Reference multiple elements in a cell array

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Andrew Bellocchio
Andrew Bellocchio 2017-11-30
回答： Stephen23 2017-12-1
Hi all, I am unsure on the best way to reference multiple elements in a cell array. Suppose I have 4 parts and each is a cell. All parts are contained within a larger cell array as:
Part01={'Exponential' 1/lambda_A 0 age1 0};
Part02={'Exponential' 1/lambda_B 0 age2 0};
Part03={'Exponential' 1/lambda_C 0 age3 0};
Part04={'Exponential' 1/lambda_D 0 age4 0};
Parts={Part01;Part02;Part03;Part04};
Each age# value is a single number. I want to create a single vector like this:
AgeVector=[age1, age2, age3, age4]
I can do so using:
PartAgeVector=[Parts{1}{4} Parts{2}{4} Parts{3}{4} Parts{4}{4}];
This seems awfully ugly and inefficient. The number of Parts will change with each use and I want to avoid manually coding like the last line of code. How may I most efficiently create a single vector.
Thank you! A.Bellocchio
  2 个评论
Stephen23
Stephen23 2017-12-1
"This seems awfully ugly and inefficient"
It is. If you simply put your numeric data into a numeric array then this entire problem goes away.
Andrew Bellocchio
Andrew Bellocchio 2017-12-1
Agreed, but my part data is conveniently organized with both text and numbers. Using cell arrays is new to me. I was hoping to learn an easy way to pull data when the array has different types of cells.

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采纳的回答

KSSV
KSSV 2017-12-1
PartAgeVector = cell2mat(cellfun(@(x) x(1,4), Parts))
  1 个评论
Andrew Bellocchio
Andrew Bellocchio 2017-12-1
编辑：Andrew Bellocchio 2017-12-1
Yay, this works well. Thank you, KSSV. I can also build the PartAgeVector using a for loop such as:
no_parts=length(Parts);
for part=1:no_parts
PartAgeVector3(part)=Parts{part}{4};
end
Still, this is bulky. Is there a way to pull the data with indexing directly like we would with a pure matrix?

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更多回答（1 个）

Stephen23
Stephen23 2017-12-1
This is trivial with a comma-separated list:
>> C = {1,11,111;2,22,222;3,33,333;4,44,444}
1 11 111
2 22 222
3 33 333
4 44 444
>> [C{:,3}]
ans =
111 222 333 444

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