Throughput performance of OFDMA

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Prabha Kumaresan
Prabha Kumaresan 2017-12-5
评论： Walter Roberson 2019-2-3
for the below mentioned code i want to plot the number of subcarriers in x axis and throughput on yaxis.but for me its showing the number of users in x axis.can anyone help me to solve this issue.
Bmax=2000000;
noise=1e-9;
p_fix=0.01;
N_UE=[ 10 20 30 40 50];
N_SC=[ 60 70 80 90 100];
for r = 1:length(N_SC)
for t= 1 :length(N_UE)
Xmax=1; % x-coordinate for base station
Ymax=1; % y-coordinate for base station
radius=5; %coverage radius
xsd=ones(1,N_UE(t))*Xmax;
ysd=ones(1,N_UE(t))*Ymax;
rrx=radius*sqrt(rand(1,N_UE(t)));
thetarx=2*pi*rand(1,N_UE(t));
ang=0:0.01:2*pi;
xrx=xsd+rrx.*cos(thetarx); %random position of receivers-->x-coordinate
yrx=ysd+rrx.*sin(thetarx); %random position of receivers-->x-coordinate
th = 0:pi/100:2*pi;
xunit = radius * cos(th) + Xmax;
yunit = radius * sin(th) + Ymax;
ratio=0.1;
c=2*pi*ratio;
for j=1:N_UE(t)
temp=[];
for n=1:N_SC(r)
nc=(n-1)*c;
entry=(1+i*nc)/(1+nc^2);
temp=[temp entry];
end
Rchan=toeplitz(temp);
[E,L]=eig(Rchan);
SQRTL=sqrt(L);
A=E*SQRTL/sqrt(2);
GG=randn(N_SC(r), 1)+i*randn(N_SC(r),1);
H=A*GG;
HH=abs(H);
as=4;
bs=10;
Lsigma=as+(bs-as)*rand(1,N_UE(t));
Lshadow=10.^(randn(1,N_UE(t)).*(Lsigma/10));
ae=3;
be=5;
Lexp=ae+(be-ae)*rand(1,N_UE(t));
for k=1:N_SC(r)
for j=1:N_UE(t)
dist2(j)=sqrt((xrx(j)-xsd(j))^2+(yrx(j)-ysd(j))^2);
G(j,k)=(F(j,k)*Lshadow(j))/dist2(j).^Lexp(j);
end
end
siz = size(G);
idx = sub2ind(siz, randi([1,N_UE(t)], 1, siz(2)), 1:siz(2));
C = zeros(siz);
C(idx) = G(idx)
throughput =((Bmax.*log(1+((p_fix).*C))./noise));
overall_throughput = sum(sum((Bmax.*log(1+((p_fix).*C))./noise)));
output(r,t)=overall_throughput;
figure
plot(throughput,'b','linewidth',2);
legend(['No.of users=' num2str(N_UE(t))])
xlabel('No of subcarriers')
ylabel('throughput')
axis square
grid on
end
end
figure
plot(output(:,1), 'color', 'r' ,'linewidth',2);hold on
plot(output(:,2), 'color', 'b' ,'linewidth',2);hold on
plot(output(:,3), 'color', 'm' ,'linewidth',2);hold on
plot(output(:,4), 'color', 'y' ,'linewidth',2);hold on
plot(output(:,5), 'color', 'g' ,'linewidth',2);hold on
xlabel('No of subcarriers [x10]')
ylabel('Overall Throughput')
legend( 'UE1','UE2','UE3','UE4','UE5','Location','best')
grid on
title('Overall throughput performance')

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回答（1 个）

Krishan Srimal
Krishan Srimal 2018-1-29
This is gives me an error. what would be the reason pls?
Attempt to execute SCRIPT throughput as a function: C:\Users\user\Documents\throughput.m
Error in throughput (line 4) plot(throughput,'b','linewidth',2);
  3 个评论
显示 1更早的评论
Ubaid Ullah
Ubaid Ullah 2019-2-3
Undefined function or variable F
Error in example (line 48)
G(j,k)=(F(j,k)*Lshadow(j))/dist2(j).^Lexp(j);
Walter Roberson
Walter Roberson 2019-2-3
Ubaid Ullah you are correct, that code does not define F or initialize F, or document what the purpose of F is. The author of the code has not posted anything for about 6 months, so I do not know if they will return to clarify it.

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