why the repeated number is lost?

Question

bing xu 2017-12-6

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/371413-why-the-repeated-number-is-lost

评论： bing xu 2017-12-11

采纳的回答： Elizabeth Reese

在 MATLAB Online 中打开

I want to synchronize 95 time series data, the code is:

combination=combnk(1:95,2) *

for k=1:length(combination)* %% k equals 1:4465 %%

m=combination(k,1) %%% Here is the problem. since k=1:4465, I would suppose m has 4465 elements but it turns out just has 94 elements. I would like to know how can I make 'm' display all elements in combination(k,1) but not lost those repeated ones%%%

n=combination(k,2)

tsa=vts(1,m)

tsb=vts(1,n)

[tsa(m),tsb(n)]=synchronize(tsa,tsb,'union');

end

%%vts is a timeseries collection which contain all the 95 time series data%%

From my code I would suppose 'm equals every element in combination first column, which should be 4465 elements. but indeed, m equals 1:94 that is 94 elements. it auto ignore repeat number like 1 is repeated 95 times in combination. I do not how to make it. Please I would like to hear all your comments. Thank you.

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Answer 1

Elizabeth Reese 2017-12-8

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/371413-why-the-repeated-number-is-lost#answer_295373

The k is what is looping up to 4465. The m value will take on all of the values in the first column of combination which is 1 through 94. Most of these numbers do repeat, so m will have the same value for multiple iterations of the loop while n changes. It is the pair of m and n that is the unique combination. You can look at combination in the Variable Window to confirm this.

If you are not seeing the output that you expect, I would step through the script using the debugger and check that tsa and tsb are assigned correctly and updated properly. Without having vts, I cannot check that.