compare between two results with percentage Error

8 次查看(过去 30 天)
Hi
can you help me with this problem , i have two results (original and calculation) , i would like to compare the original with calculation results and have the percentage error in calculation part when compare with original . for example if i have
Original =[1;2;3;1;2;3]; calculation=[1;2;3;1;2;3];
the calculation is exact the original so the percentage Error in calculation is 0% if i have
Original =[1;2;3;1;2;3]; calculation=[1;1;3;2;2;1];
the calculation is not exact the original so the percentage Error in calculation has to be 50%
thank you

回答(1 个)

Alizée Perrin
Alizée Perrin 2017-12-6
Your question is similar to this one.
Try this code :
PDif = 100*(calculation-original)./original;
  1 个评论
mohammed hussein
mohammed hussein 2017-12-6
thank you for your answer . i want to compare not by number but by similarity in numbers . if it is similar OK if it is not so it is wrong . the percentage is based on similarity in number .

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