Histograms for image processing

2017 12 6
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更新时间：2017 12 6
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Hi, I need some explanation for the following code we wrote in class today:
function [imageMapped] = L1_image_map(image,T)
imageMapped = zeros(size(image));
for channel = 1:size(image,3)
for ii= 1:size(image,1)
for jj=1:size(image,2)
imageMapped(ii,jj, channel)=T(image(ii,jj,channel) +1,channel);
end
imageMapped = im2uint8(imageMapped);
end
end
end
Where T is the transformation function T=255*CDF. Thanks!

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Image Analyst
Image Analyst 2017-12-6
编辑：Image Analyst 2017-12-6

0 个投票

Why should there be T=255*CDF? You'd use the CDF to create T if you were doing a histogram equalization, but this function doesn't do that (unless you passed in a T of that).
This code is basically a look up table operation, the kind of thing done by the function intlut(). It changes the gray level of the image based on what the value is in the index of T. For example if T(5) is 100, then a gray level of 4 would get mapped/changed to a gray level of 100.
  1. T(1) is the new gray level for pixels with a value of 0.
  2. T(2) is the new gray level for pixels with a value of 1.
  3. T(3) is the new gray level for pixels with a value of 2.
  4. etc.

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