Function not returning full matrix

2017 12 8
1 个回答
回答已采纳
更新时间：2017 12 11
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0 个投票

I have a matrix around 20,000 by 20 and when I use this codes it only returns 1000 by 20. I'm sure the problem has to be on the for loop I just don't know how to get this function to show me the whole matrix.
function ....
i=length(data_2);
for i=1:data_2
fprintf...
.....
end
end

13 个评论
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KSSV
KSSV 2017-12-8
Don;t use length.......check with size. length gives you only maximum dimension......
Stephen23
Stephen23 2017-12-8
Never use length in your code, because its output is not very useful. Use size or numel as required, but never use length.
Jos (10584)
Jos (10584) 2017-12-8
These two lines are weird (and wrong)!
i=length(data_2);
for i=1:data_2_
I think you want something like
N = numel(data_2_)
for i=1:N
Rafael
Rafael 2017-12-8
编辑：Rafael 2017-12-8
numel fixed the problem. However, now I'm getting another problem since I changed
i=length(data_2) to N=numel(data_2)
The errors says, Index exceeds matrix dimensions.
Error in project (line6)
fprintf('%5.0f', data_2(i,1));
If I change the i to an N it says the same thing as if I leave it as an i.
James Tursa
James Tursa 2017-12-8
Please show the current entire code snippet that is causing the problem.
Rafael
Rafael 2017-12-8
function [i]=table(data_2)
clc
fprintf('A B C D E F G H I J K L M N O P\n');
N=numel(data_2);
for i=N
fprintf('%1.0f',data_2(i,1));
fprintf('%1.0f',data_2(i,2));
fprintf('%1.0f',data_2(i,3));
fprintf('%1.0f',data_2(i,4));
fprintf('%1.0f',data_2(i,5));
fprintf('%1.0f',data_2(i,6));
fprintf('%1.0f',data_2(i,7));
fprintf('%1.0f',data_2(i,8));
fprintf('%1.0f',data_2(i,9));
fprintf('%1.0f',data_2(i,10));
fprintf('%1.0f',data_2(i,11));
fprintf('%1.0f',data_2(i,12));
fprintf('%1.0f',data_2(i,13));
fprintf('%1.0f',data_2(i,14));
fprintf('%1.0f',data_2(i,15));
fprintf('%1.0f',data_2(i,16));
fprintf('\n')
end
end
James Tursa
James Tursa 2017-12-8
See the Answers below to fix your problem. E.g.,
N = size(data_2, 1);
Rafael
Rafael 2017-12-8
whos data_2 returns
Name Size Bytes Class Attributes
data_2 20,000x20 44k double
Rafael
Rafael 2017-12-8
What do you mean in plain English. It's exactly what I said. I created a function that puts label on top of each columns. The problem is that it's not returning the whole matrix when I call it. It only returns 1000 by 20 matrix instead of the 20,000 by 20. So, when I use size(data_2,1) it only returns the last row of the matrix.
Rafael
Rafael 2017-12-8
I know it sounds confusing. If you'd see it you would understand what I am trying to do.
To make it clear. I have an array or matrix that has 20,000 rows and 20 columns. When I call the matrix which is called data_2 it returns the whole matrix like this,
Column 1 through 13
.................
Column 14 through 20
.................
I created a function which organize the matrix and puts label on top of each columns like this,
A B C D E F G...
1 2 3 4 5 6 7...
1 2 3 4 5 6 7...
So, the problem is that when I created this function and I called it returns only 1000 rows and 20 columns. It is not returning the whole matrix which is what I want.
function ....
i=length(data_2);
for i=1:data_2
fprintf...
.....
end
end
If I use,
i=size(data_2,1)
n=1:i
It only returns the last row from the matrix.
Rafael
Rafael 2017-12-8
If I run that it returns the whole matrix which is what I want. Now, it doesn't return the headers and it returns the matrix in the wrong order.
Rafael
Rafael 2017-12-8
Yes, I understand you were just giving me an example. I did have something inside that, but it is not returning on top of the columns. I copy you exact code for fprintf.
The order is from 10 13 7 up to row 20,000 for rows and columns is from 1 to 20. These codes returned it as 39 3 41 etc.
Rafael
Rafael 2017-12-9
The table is something like this, It goes from column 1 to 20 and row 1 to 20,000.
1 2 3 4 5 6 ... 20
10 13 17 43 76 42... 23
.
.
.
20,000
What I explained is that when I run the code you provided me, it returns those numbers in a different order like this,
1 2 3 4 5 6 ... 20
39 3 41 43 9 56... 1
.
.
.
18,390

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 采纳的回答

Rafael
Rafael 2017-12-10

0 个投票

Okay, now when I do which cssm is working. It tells me where it is saved.

5 个评论
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Rafael
Rafael 2017-12-10
编辑：Rafael 2017-12-10
That's where I am getting confused. What is data? I know cohl is the string. Is just telling me undefined function for data.
Rafael
Rafael 2017-12-10
The issue is when I tried to run your code,
colh = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T'};
data = permute( reshape( (1:120), 20,6 ), [2,1] );
fprintf( 1, [repmat( '%4s, ' , 1,20 ),'\n'], colh{:});
fprintf( 1, [repmat( '%4.0f, ', 1,20 ),'\n'], data );
This returns a 6 rows and 20 columns matrix with the strings on top. So, when I tried to run this,
cssm(data,colh)
It returns, Error using cssm Too many input arguments.
Rafael
Rafael 2017-12-10
function [colh]=cssm( data_2)
clc
colh = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P'};
fprintf( [repmat( '%4s, ', 1,16 ),'\n'], colh{:} )
N = size( data_2, 1 );
for ii = 1 : N
fprintf([repmat('%4.0f, ',1,16),'\n'], data_2(ii,:))
end
end
Rafael
Rafael 2017-12-10
Okay, I changed it. Now when I run cssm(data,colh) it returns the matrix from column 1 to 20 and row 1 to 101. Organized.
Rafael
Rafael 2017-12-11
It returned the strings and the data which looks organized like in the original. However, it return it horizontally which doesn't fit in the command windows. It return and error.

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