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A question about the histograms please

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MAHMOUD ALZIOUD 2017-12-14

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关闭： MATLAB Answer Bot 2021-8-20

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Hi everyone, As can be seen in the attached image, my histogram is built using counts, I WROTE THE FOLLOWING CODE TO CONVERT COUNTS TO %, how can i know exactly the percent of each load bin

figure, 
>> histogram([tandem{K}]);
ylabels = get(gca, 'YTickLabel');
ylabels = linspace(0,100,length(ylabels));
set(gca,'YTickLabel',ylabels);

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the cyclist 2017-12-14

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编辑：the cyclist 2017-12-14

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As described in the documentation for the histogram function, you can used the 'Normalization' input parameter:

histogram(tandem{K},nbins,'Normalization','probability')

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thank you very much, this worked, but i still have to know what is the percentage of each load bin, because i am trying to make a table of each load bin with its %.

Image Analyst 2017-12-14

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Simply multiply by 100! (Did you look at the help documentation?)

histObject = histogram(tandem,nbins,'Normalization','probability')
percentages = 100 * histObject.Values

Steven Lord 2017-12-14

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Call histogram and specify the 'probability' Normalization as the cyclist showed, but specify an output argument when you call it. Then get the Values property of the handle returned from histogram. Alternately, if you don't need the graphics object call histcounts with that same Normalization option.

MAHMOUD ALZIOUD 2017-12-14

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yes i just tried it and it worked, one last question please, what if i want to define the ranges of bins as follows, 4o bins with a range of 6000:2000:82000, where can i put this piece of data in the code?

MAHMOUD ALZIOUD 2017-12-14

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编辑：MAHMOUD ALZIOUD 2017-12-14

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this is my code: the missing piece is how to tell him make me 40 bins with 2000 of width for each bin and starting from 6000 to 82000

figure
  histObject =histogram(tandem{K},40,'Normalization','probability')
  percentages = 100 * histObject.Values
      xlabel('Load in Kips')
      ylabel('Normalized Percentages')
      title(['ALS for C9 Tandem For Month ',num2str(months),' ', 'Station' ,' ', num2str(stations)])

Image Analyst 2017-12-14

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Try this:

edges = linspace(6000, 82000, 41); % 41 edges for 40 bins.
histObject =histogram(tandem{K}, edges, 'Normalization', 'probability')

MAHMOUD ALZIOUD 2017-12-14

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i tried it and i lost the histogram, it became with no data in it !

the cyclist 2017-12-14

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I'm confused. It sounds like you are trying to specify values that are in the range on the y-axis. You should be specifying the edges of the bins with the values of the x axis. So maybe you just want

linspace(0,40,41)

instead of what you did.

You also don't really need to use linspace for that. The vector

0:40

will give the same.

MAHMOUD ALZIOUD 2017-12-14

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Dear, I am trying to organize the bins based on the x-axes values, my x-axis must start with 0 to 82000, in which this range must hold 40 bins of the histogram, is it clearer now?

the cyclist 2017-12-14

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OK, then

linspace(0,82000,41)

should work. But the figure you posted here has x-axis that are in the range 0-60 ("Load in Kips"), so I'm still a bit confused. (Maybe you just relabeled the X tick labels?)

MAHMOUD ALZIOUD 2017-12-14

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yes you are right, the thing is i have 10 text files i am analyzing, one of the is the attached image in which the range ends at 60 Kips, the other files they end at 80 kips (kips means one thousand pounds), that is why i need to unite the whole 10 figures in one common range.

Image Analyst 2017-12-14

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Is your data in the range 0 to 80, or 0 to 80,000? Either way, just use linspace and put in the overall min and overall max, and the number of bins you want to form the edges.

MAHMOUD ALZIOUD 2017-12-14