How to set Time Axis

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Abhishek Savita
Abhishek Savita 2017-12-15
评论： Abhishek Savita 2017-12-20
Hi Folks
I have a data in which time axis set in following format
ncdisp('myfile.nc')
time
Size: 39x1
Dimensions: time
Datatype: single
Attributes:
standard_name = 'time'
long_name = 'time'
units = 'months since 1970-01-01 00:00:00'
axis = 'T'
climatology = 'climatology_bounds'
year=ncread('myfile.nc','time')
year=
9×1 single column vector
6
18
30
42
54
66
78
90
102
114
126
138
150
162
174
186
198
210
222
234
246
258
270
282
294
306
318
330
342
354
366
378
390
402
414
426
438
450
462
But i want to convert variable year(6,18,30,...,462) to year(1:39), which represent 1 as 1970 and 39 as 2008;
I mean
year(1)=1970
year(2)=1971
.
.
.
year(39)=2008
Could you please suggest me, how can I make it ?
Thanks in advance

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采纳的回答

Walter Roberson
Walter Roberson 2017-12-20
ncmon = ncread('myfile.nc','time');
year = 1970 + floor((ncmon - 1) / 12);
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显示 1更早的评论
Walter Roberson
Walter Roberson 2017-12-20
ncmon = ncread('myfile.nc','time');
year_index = 1 + floor((ncmon - 1) / 12);
calendar_year = 1970 + year_index - 1;
ohc_18_new=h18_hc(:,:,:,year_index);
Abhishek Savita
Abhishek Savita 2017-12-20
Thank you very much Walter, it is now.

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更多回答（1 个）

James Knowles
James Knowles 2017-12-20
I am sure there is a more elegant and simpler solution out there but this will function as you desire.
year = [6
18
30
42
54
66
78
90
102
114
126
138
150
162
174
186
198
210
222
234
246
258
270
282
294
306
318
330
342
354
366
378
390
402
414
426
438
450
462];
YEAR = zeros(39,1); %this will become the vector you desire
for i=1:39
years_passed = floor(year(i)/12);
YEAR(i) = 1970+years_passed;
end

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