How to compare two vectors with different dimensions to get logical array?

2 次查看(过去 30 天)
Hello, I have two vectors with different dimensions. To make it simple,lets say A=[775.4; 770.2; 690;...] is n by 1 and B is m by 2: for example, B(1,:)=775.446,774.706. Basically, I want this: if A(i,1)<=B(i,1) & A(i,1)>=B(i,2) is true,then do sth. i tried to use for statement such as for i=size(A),obviously, theres problem because of the two dimensions. If anybody knows how to solve this problem, please let me know. Thanks.
  3 个评论
Lei
Lei 2012-5-3
Hi Sean,
Thanks for your help!
Yes,I want to do this for each value of A.
What I want is: if each of the value of A is in the range of row of B ( because each row of my B has two values). Then I do sth else. The reason i did not put the other code is here is that they look complicated.
In my case, my A is 700 by 1 and my B is 30 by 2.
Any of your help will be appreciated!

请先登录,再进行评论。

采纳的回答

Jan
Jan 2012-5-3
A = rand(10, 1);
B = rand(20, 2);
n = min(size(A, 1), size(B, 1));
R = A(1:n) <= B(1:n, 1) & A(1:n) >= B(1:n, 2);
for i = 1:n
if R(i)
...
end
end
Or:
n = min(size(A, 1), size(B, 1));
for i = 1:n
if A(i) <= B(i, 1) & A(i) >= B(i, 2)
...
end
end
  2 个评论
Lei
Lei 2012-5-3
Hi Jan,
What if the size of A is larger than the size of B?
What can I do to solve this problem? Actually,I did not notice this until i tried to run my own code.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Sparse Matrices 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by