Splitting array based on a single column's condition
11 次查看(过去 30 天)
显示 更早的评论
Hello, I am trying to separate my large array of [n rows, 5 columns] into individual arrays of [k rows, 5 columns] (where k < n). I want to split my array based on numbers on my fourth column. The fourth column has numbers that increase and decrease in a loop to create some peaks (example: goes from 0 to 35, then from 35 goes to 0, then from 0 to -35, etc.).
I've attached a sample code to help better explain what I mean.
Is there an efficient way to split these data? (So far I've been going into the data selecting where I want to split them up, and doing it manually.)
Thank you in advance.
采纳的回答
Ramnarayan Krishnamurthy
2017-12-28
编辑:Ramnarayan Krishnamurthy
2017-12-28
If the transition point in the fourth column is known to be 0, then you can consider splitting the data by the location of these 0's.
% Locate the zeros in the 4th column
index_0 = find(s_P1_5(:,4)==0);
% Include the start and end indices
idx = [0 index_0' size(s_P1_5,1)];
% Create individual cells containing the sub matrices
out = mat2cell(s_P1_5, diff(idx))
The split arrays will now be stored in out{1}, out{2} and so on.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Matrices and Arrays 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!