Create Legend From Array

341 次查看（过去 30 天）
Christopher Saltonstall
编辑： KL 2017-12-19
Hello,
I have an array
nN = 6;
N = 1:nN;
I want to make a legend where nN changes and so may not be known ahead of time. I found the following solution on another post, but it doesn't work for me.
legendCell = cellstr(num2str(dope, 'N=%-d'));
legend(legendCell)
I get the error.
Error using legend>process_inputs (line 563)
Cell array argument must be a cell array of character vectors.
Error in legend>make_legend (line 328)
[autoupdate,orient,location,position,children,listen,strings,propargs]
= process_inputs(ha,argin); %#ok
Error in legend (line 282)
make_legend(ha,args(arg:end),version);
So, I tried
for iN = 1:nN
legendCell{iN} = cellstr(['n = ' num2str(N(iN))]);
end
legend(legendCell)
which gives a similar error. However, the following does work.
legendCell = {'n=1', 'n=2', 'n=3', 'n=4', 'n=5', 'n=6'};
legend(legendCell)
Why does the later work but the others don't?

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采纳的回答

Jos (10584)
Jos (10584) 2017-12-19
In the first two codes, legendCell is a cell array of cells ( = {{..} {...}} ) rather than a cell array of strings (= {'..' '..'})! You have a pair of curly braces too many, as cellstr creates a cell, which you then put into a cell :)
Try this:
for iN = 1:nN
legendCell{iN} = num2str(N(iN),'N=%-d');
end

更多回答（1 个）

KL
KL 2017-12-19
编辑：KL 2017-12-19
Without a loop maybe,
legendCell = strcat('N=',string(num2cell(1:nN)))
and then as you might know,
legend(legendCell)

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