Returning Variables as Characters

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Trevor Badji
Trevor Badji 2017-12-21
评论： Walter Roberson 2017-12-26
I have function such that
a= rand (1,10); % it generates random real numbers from 0 to 1
i=1:10;
if b(i)< 0.4;
b(i)= 'A';
else if
b(i) = 'B'
end
the purpose of this code is for example
b = 0.23 0.45 0.89 0.74 0.48 0.98 0.12 0.05 0.56 0.14
I want it to return as a result
b= A B B B B B A A B A
  2 个评论
Guillaume
Guillaume 2017-12-21
@Dogukan,
We really don't appreciate when the original poster edit their question away once they've got an answer. This is not a private consulting service. The answers we post are not just for you, they're intended to help anybody with the same issue. If you edit the question away, the answers become meaningless.
It also makes us a lot less likely to answer your questions in the future.
Thankfully, MathWorks doesn't like it either and have a policy of restoring questions edited away to their original state, so it's also pointless.

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回答（2 个）

Stephen23
Stephen23 2017-12-21
编辑：Stephen23 2017-12-21
method one: character code:
>> b = char(66-(a<0.4))
b = ABBBBBAABA
method two: sprintf:
>> b = sprintf(' %c',66-(a<0.4))
b = A B B B B B A A B A
method three: indexing (char):
>> c = 'AB';
>> b = c(2-(a<0.4))
b = ABBBBBAABA
method four: indexing (cell):
>> c = {'A','B'}65_66
>> b = c(2-(a<0.4))
b = 'A' 'B' 'B' 'B' 'B' 'B' 'A' 'A' 'B' 'A'
method five: generate characters directly using randi:
>> char(randi([65,66],1,10))
ans = ABBBBBAABA
Pawel Jastrzebski
Pawel Jastrzebski 2017-12-21
编辑：Pawel Jastrzebski 2017-12-21
clear all;
clc;
data = rand (1,10)
%logical vector to establish when datapoint is 'A' and 'B'
% Condition 1: 'A' if 'data <= 0.5'
% Condition 2: 'B' if 'data > 0.5'
logicValA = data <= 0.5;
logicValB = data > 0.5;
% Use logical vectors to separate 'data' into 'A's' and 'B's':
% 'newData' as 'char vector' → all values concatenated
newData(logicValA) = 'A'
newData(logicValB) = 'B'
% 'newData1' as 'cell array' → all values separated
newData1 = {}
newData1(logicValA) = {'A'}
newData1(logicValB) = {'B'}
  2 个评论
Trevor Badji
Trevor Badji 2017-12-21
编辑：Matt J 2017-12-21
clear all;
clc;
N=10;
probVector = [0.4 0.05 0.2 0.15 0.2];
b = rand (1,N)
%logical vector
% 'A' if 'data <= 0.5'
% 'B' if 'data > 0.5'
logicValA = 0<b<=probVector(1);
logicValB = probVector(1)< b <probVector(1)+probVector(2);
logicValC = probVector(1)+ probVector(2)<b<= probVector(1)+probVector(2)+probVector(3);
logicValD = probVector(1)+ probVector(2)+probVector(3)<b<=probVector(1)+probVector(2)+probVector(3)+probVector(4);
logicValE = probVector(1)+probVector(2)+probVector(3)+probVector(4)<b<= probVector(1)+probVector(2)+probVector(3)+probVector(4)+probVector(5);
% 'newData' as 'char vector' → all values concatenated
newData(logicValA) = 'A'
newData(logicValB) = 'B'
newData(logicValC) = 'C'
newData(logicValD) = 'D'
%newData(logicValE) = 'E'
% 'newData1' as 'cell array' → all values separated
newData1 = {}
newData1(logicValA) = {'A'}
newData1(logicValB) = {'B'}
newData1(logicValC) = {'C'}
newData1(logicValD) = {'D'}
newData1(logicValE) = {'E'}
I have changed my code regarted to yours but now it only returns E what is the missing point ?
Walter Roberson
Walter Roberson 2017-12-26
A<B<C means to compare A and B first getting out 0 (false) or 1 (true), and then to compare that 0 or 1 to C. You need to test A<B&B<C

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