Comparing images using morphological operations only
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I have to detect numbers on license plate through comparing them with the digits numbers images, only using morphology, but i get stuck after segmenting the digits and while comparing both images "9 from plate & 9 original image" ANDing gives me partially wrong answer
% max = -99999;
% bothTrue = IMG & One;
% NumPixels = sum(bothTrue(:));
% if NumPixels>max
% max=NumPixels;
% Digit=1;
% end
and getting the near "Extent area" fails also
min=100000;
A=sqrt((0.4913)^2-Anum^2); //this number i observed from the extent of image of digit"1"
if A<min
Digit=1;
min=A;
end
So is there someway to solve it using morph and logical operations only?
2 个评论
Stephen23
2017-12-22
@koks paul: this is not twitter. I removed the ugly # characters from your tags, and separated them correctly using commas.
回答（2 个）
Walter Roberson
2017-12-22
No. The calculation
A=sqrt((0.4913)^2-Anum^2);
is not a morphological calculation.
Morphological operations transform one matrix to another matrix, but morphological operations never make decisions about what the input or output matrices mean. You always need a non-morophological operation to interpret the results of the transformation.
Image Analyst
2017-12-22
0 个投票
I don't know how to do it using morphology (dilation, erosion, opening, and closing). You can do it using logical operations (and, or, exclusive or, not). Try using the Dice Sorensen coefficient (demo attached).
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2017-12-23
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