Problem "Invalid first data argument" when plot a figure
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Dear Colleagues My name is Le Thanh Ha. I am quite new to Matlab. I write a code to draw a figure, but the problem came out like "Invalid first data argument" and I do not know to what is the problem and how to figure out it. Please give me some advice to overcome it. Any comment and suggestion is greatly appreciated. Best
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采纳的回答
ANKUR KUMAR
2017-12-25
hold on
x=(1:127);
col={'b','r','k','y'}
data={vxo_cycle*0.1,gdp_cycle*0.01,pi_cycle,hoursworked_cycle}
for ii=1:4
plot(x,data{ii},col{ii})
hold on
end
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ANKUR KUMAR
2017-12-26
编辑:ANKUR KUMAR
2017-12-26
for legends
Just type legends once the loop ends
For example
A={randi(25,1,121),randi(25,1,121),randi(25,1,121),randi(25,1,121)} %You can write only one time. As it changes after execution
x=(1:121);
col={'r','b','k','g'}
for i=1:4
plot(x,A{i},col{i})
hold on
end
legend('First Data','Second Data','ThirdData','Fourth Data')
更多回答(1 个)
Walter Roberson
2017-12-26
ppp=plot(1:127,vxo_cycle*0.1,'b',1:127,gdp_cycle*0.01,'r',1:127,pi_cycle,'k','LineWidth',hoursworked_cycle,'y','LineWidth',1.5);
has 'LineWidth' and then a variable. The 'LineWidth' is a named option and once you have started named options you cannot have any more positional parameters. However after that you then have 'y' which is not one of the named options: it is a positional line style option. But if there did happen to be a named option beginning with 'y' it would have to be followed by a value, which in this case would have to be that second 'LineWidth'. Then after that you have 1.5 which is not a valid option name.
Probably the first LineWidth should have been a variable name.
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