Error using sortrows (line 63) COL must be a vector of column indices into X. Error in newton (line 77) vardmy=sortrows(var,-1);. what does mean by this error ? how to remove it?

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swati paliwal 2017-12-26

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https://ww2.mathworks.cn/matlabcentral/answers/374516-error-using-sortrows-line-63-col-must-be-a-vector-of-column-indices-into-x-error-in-newton-line

评论： Walter Roberson 2018-1-29

%........ fitness calculation..................
          pufmx=vnucsh(n,1)*1.00;         % varible constarints on puf
          pufmn=vnucsh(n,1)*0.9;
          nucsh=[vnucsh(n,1);vnucsh(n,2)];
          fitness=fit_fun(nucsh);
          if(fitness~=0)
              var=[var;fitness;nucsh(1);nucsh(2)];     % calling fitness function
              nro=nro+1;
          end
      end
     vardmy=sortrows(var,-1);
     vardmy1=vardmy(1,:);         % one highest fitness variable
     maxvarfit=vardmy1(1);        % maximum fitness

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Answer 1

Walter Roberson 2017-12-26

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在 MATLAB Online 中打开

In current versions of MATLAB, sortrows with a negative column number means to sort in descending order on that column..

You could do a sortrows(var,1) and then

vardmy1=vardmy(end,:);

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swati paliwal 2017-12-27

sir i run the code and in command window no error is showing. Downwards it is showing busy but from 4 hours it remains same i.e is busy.... what is this means.what should i do??

Walter Roberson 2017-12-27

Sorry, you have not posted enough of the code for me to speculate on the reason.

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Answer 2

swati paliwal 2018-1-28

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此回答的直接链接

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编辑：Walter Roberson 2018-1-28

在 MATLAB Online 中打开

function gsa_nr_method
clear all;
clc;
close all;
global pufmn pufmx xmmn xmmx
global ismx vlmn vlmx
global pmax MRT_55 otprmx 
N=50; 
 max_it=1000; 
 ElitistCheck=1; Rpower=1;
 min_flag=1; % 1: minimization, 0: maximization
F_index=1;
Rnorm=2;
[Fbest,Lbest,BestChart,MeanChart]=GSA(F_index,N,max_it,ElitistCheck,min_flag,Rpower);
 Fbest,semilogy(BestChart,'--k')
 title(['\fontsize{12}\bf F',num2str(F_index)]);
 xlabel('\fontsize{12}\bf Iteration');ylabel('\fontsize{12}\bf Average Best-so-far');
 legend('\fontsize{10}\bf GSA',1);

gsa program~

function [Fbest,Lbest,BestChart,MeanChart]=GSA(F_index,N,max_it,ElitistCheck,min_flag,Rpower)
%V:   Velocity.
%a:   Acceleration.
%M:   Mass.  Ma=Mp=Mi=M;
%dim: Dimension of the test function.
%N:   Number of agents.
%X:   Position of agents. dim-by-N matrix.
%R:   Distance between agents in search space.
%[low-up]: Allowable range for search space.
%Rnorm:  Norm in eq.8.
%Rpower: Power of R in eq.7. 
% Rnorm=2; 
 %get allowable range and dimension of the test function.
[down,up,dim]=test_functions_range(F_index); 
%random initialization for agents.
X=initialization(dim,N,up,down); 
%create the best so far chart and average fitnesses chart.
BestChart=[];MeanChart=[];
V=zeros(N,dim);
for iteration=1:max_it
%     iteration
      %Checking allowable range. 
      X=space_bound(X,up,down); 
      %Evaluation of agents. 
      [fitness]=evaluateF(X,F_index)
      if min_flag==1
      [best, best_X]=min(fitness); %minimization.
      else
      [best, best_X]=max(fitness); %maximization.
      end        
      if iteration==1
         Fbest=best;Lbest=X(best_X,:);
      end
      if min_flag==1
        if best<Fbest  %minimization.
         Fbest=best;Lbest=X(best_X,:);
        end
      else 
        if best>Fbest  %maximization
         Fbest=best;Lbest=X(best_X,:);
        end
      end
BestChart=[BestChart Fbest]
MeanChart=[MeanChart mean(fitness)]
%Calculation of M. eq.14-20
[M]=massCalculation(fitness,min_flag); 
%Calculation of Gravitational constant. eq.13.
G=Gconstant(iteration,max_it); 
%Calculation of accelaration in gravitational field. eq.7-10,21.
Rnorm=2;
a=Gfield(M,X,G,Rnorm,Rpower,ElitistCheck,iteration,max_it);
%Agent movement. eq.11-12
[X,V]=move(X,a,V); 
end %iteration

I am getting this error again and again but unable to understand the error between these.....please help

Error in gsa_nr_method (line 40)
[Fbest,Lbest,BestChart,MeanChart]=GSA(F_index,N,max_it,ElitistCheck,min_flag,Rpower);

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swati paliwal 2018-1-29

How can we hire a consultant...Is it cost something?

Walter Roberson 2018-1-29

Yes, it costs something; depending on who you hire, it could end up costing a lot. That is the price of privacy.

The volunteers here donate their time to benefit everyone, expecting that the questions and answers will be public so that everyone can learn from them and everyone can contribute. However, the volunteers often decline to answer private questions as private questions get into "work" and people expect to be paid for work.

I am not sure who is available as a consultant these days. Yair possibly -- but Yair is a professional and expects to be paid for private professional services. Some of the more active volunteers might agree to being hired, if the topic interests them and they do not have anything else to do. I am not accepting contracts these days.

Mathworks offers a consulting service; I do not know how much they charge.

You can probably find MATLAB consulting services online, possibly even close to you. I would suggest, though, that if you hire one of the "5 dollars for any program" services that you should not trust that your code will stay confidential.

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