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Why ParFor does not work for this?

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Erdem Uguz
Erdem Uguz 2017-12-27
回答： Namnendra 2022-6-19
It is a really simple manipulation. I want to replace some lines of the matrix with zeros.
A=rand(20,20);
for j=1:1:4
A(4*j+1,:)=zeros;
end
When I replace for with parfor I get a classification error. But the results of the manipulation is independent from each other. I don't understand why.
Thank you Erdem

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Namnendra
Namnendra 2022-6-19
All variables referenced at the top level of the parfor must be resolved and classified. Go through the following link to know more :-
https://lost-contact.mit.edu/afs/inf.ed.ac.uk/group/teaching/matlab-help/R2016b/distcomp/classification-of-variables-in-parfor-loops.html
You can try putting the body of perfor loop into a function and calling the function from the loop.
I hope this helps.

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