Why ParFor does not work for this?

1 次查看（过去 30 天）
Erdem Uguz
Erdem Uguz 2017-12-27
回答： Namnendra 2022-6-19
It is a really simple manipulation. I want to replace some lines of the matrix with zeros.
A=rand(20,20);
for j=1:1:4
A(4*j+1,:)=zeros;
end
When I replace for with parfor I get a classification error. But the results of the manipulation is independent from each other. I don't understand why.
Thank you Erdem

请先登录，再回答此问题。

回答（1 个）

Namnendra
Namnendra 2022-6-19
All variables referenced at the top level of the parfor must be resolved and classified. Go through the following link to know more :-
https://lost-contact.mit.edu/afs/inf.ed.ac.uk/group/teaching/matlab-help/R2016b/distcomp/classification-of-variables-in-parfor-loops.html
You can try putting the body of perfor loop into a function and calling the function from the loop.
I hope this helps.

类别

在 Help Center 和 File Exchange 中查找有关 Parallel for-Loops (parfor) 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by