How to replace certain numbers in an array

2018 1 2
2 个回答
回答已采纳
更新时间：2018 1 2
7 次查看（30 天）

0 个投票

Could anybody help me solve the problem please? I have a sample array a=[6 8 7 4 12 10 16 11], I would like to replace all numbers greater than 10(>10) to be 20-a, the expected result should be a=[6 8 7 4 8 10 4 9]. Thank you very much.

请先登录，再回答此问题。

 采纳的回答

Image Analyst
Image Analyst 2018-1-2

1 个投票

Try this:
a=[6 8 7 4 12 10 16 11]
% Find indexes more than 10:
indexesToReplace = a > 10;
% Replace the index values with 20 minus the original number (20-a)?
a(indexesToReplace) = 20 - a(indexesToReplace)

更多回答（1 个）

KSSV
KSSV 2018-1-2
编辑：KSSV 2018-1-2

1 个投票

a=[6 8 7 4 12 10 16 11] ;
a(a>10) = 20-a(a>10) ;

2 个评论
显示 无 隐藏 无

MS SIM
MS SIM 2018-1-2
Thanks for the answer. However, this replaces the number greater than 10 with 20. How about replacing the number with 20 minus the original number (20-a)?
KSSV
KSSV 2018-1-2
编辑：KSSV 2018-1-2
okay....a was the original number.....edited the answer.

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by