Trying to use interpn - converting sample data into ndgrid format
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I'm trying to use the function interpn but it requires that I have everything in the ndgrid format. For example, I'm trying to execute this function:
Vq = interpn(X1,X2,X3,V,Xq1,Xq2,Xq3);
I'm trying interpolate the value of V given three variables (i.e. performing a 3D interpolation). I have X1, X2, and X3 set up:
X1 = 1:100; X2 = 1:50; X3 = 1:10;
That is, there are 100 points in X1, 50 points in X2, and 10 points in X1. However, my V is composed differently - it is a (100*50*10) by 1 vector, with each value in V corresponding to each value of X1, X2, and x3. In a sense, V looks like
[v(x1_1, x2_1, x3_1), v(x1_2, x2_1, x3_1), ... v(x1_100, x2_1, x3_1), v(x1_1, x2_2, x3_1), v(x1_2, x2_2, x3_1), ...].
How can I convert V into the ndgrid format?
I know that I can use griddatan but it is awfully slower than interpn.
回答(2 个)
Star Strider
2018-1-5
0 个投票
2 个评论
jh2011
2018-1-5
Star Strider
2018-1-5
You can use ‘X1’, ‘X2’, and ‘X3’ as inputs to ndgrid.
‘V is composed differently - it is a (100*50*10) by 1 vector’
‘V’ is a matrix by that definition. Vectors are by definition (Nx1). If it is in fact a vector, use reshape to create it as a matrix.
Walter Roberson
2018-1-5
reshape(V, 100, 50, 10)
2 个评论
jh2011
2018-1-5
Walter Roberson
2018-1-5
If V is based on a rectangular grid, then reshape() it into grid form according to how it is laid out, and then if needed permute() it into ndgrid order.
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