Index exceeds matrix dimensions problem with this code below :-

2018 1 7
2 个回答
回答已采纳
更新时间：2018 1 7
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0 个投票

c =
1 1 1 6
2 4 2 16
-1 5 -4 -3
N = length(c);
tol= 1e-6;
for ii=1:N-1
for jj=ii+1:N
if abs(c(jj,ii))> tol
fac=c(ii,ii) / c(jj,ii);
c(jj,:) = fac*c(jj,:) - c(ii,:);
end
end
end
how to solve this problem? that code for Gauss elimination when I press enter it appear " Index exceeds matrix dimensions "

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 采纳的回答

ANKUR KUMAR
ANKUR KUMAR 2018-1-7

0 个投票

c =[1 1 1 6; 2 4 2 16; -1 5 -4 -3]
N = size(c,1)
M=size(c,2)
tol= 1e-6;
for ii=1:M-1
ii
for jj=ii+1:N
jj
if abs(c(jj,ii))> tol
fac=c(ii,ii) / c(jj,ii);
c(jj,:) = fac*c(jj,:) - c(ii,:);
end
end
end
Instead of writing length(c), you should to define the size along first and second dimension of matrix, i.e. define the number of row and columns of matrix.

更多回答（1 个）

Walter Roberson
Walter Roberson 2018-1-7

0 个投票

length() of a 3 x 4 array is 4. length() is not the number of rows: length() is defined as:
  • 0 if any dimension of the array is 0; or
  • max() of size() of the array otherwise.

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