matrix as desired data using for loop

2018 1 10
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更新时间：2018 1 10
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suppose I had following matrix A
A(1,:)=[10 10 0.2 0 0]; A(2,:)=[10 10 10 0.3 0]; A(3,:)=[10 0.5 0 0 0];
Now I want a cell array B like this
B= [{5*5};{5*5};{5*5}];
like
B(1)=[10 10 0.2 0 0;0 10 10 0.2 0;0 0 10 10 0.2;0.2 0 0 10 10;10 0.2 0 0 10]
similarly create
B(2)=[[10 10 10 0.3 0;0 10 10 10 0.3;03 0 10 10 10;10 0.3 0 10 10;10 10 0.3 0 10]
and B(3) also.
thanks

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Stephen23
Stephen23 2018-1-10
编辑：Stephen23 2018-1-10

1 个投票

In just two lines (could easily be written in one line):
>> A = [10,10,0.2,0,0;10,10,10,0.3,0;10,0.5,0,0,0];
>> fun = @(v)toeplitz(v(1,[1,end:-1:2]),v(1,:));
>> B = cellfun(fun,num2cell(A,2),'uni',0);
>> B{:}
ans =
10.00000 10.00000 0.20000 0.00000 0.00000
0.00000 10.00000 10.00000 0.20000 0.00000
0.00000 0.00000 10.00000 10.00000 0.20000
0.20000 0.00000 0.00000 10.00000 10.00000
10.00000 0.20000 0.00000 0.00000 10.00000
ans =
10.00000 10.00000 10.00000 0.30000 0.00000
0.00000 10.00000 10.00000 10.00000 0.30000
0.30000 0.00000 10.00000 10.00000 10.00000
10.00000 0.30000 0.00000 10.00000 10.00000
10.00000 10.00000 0.30000 0.00000 10.00000
ans =
10.00000 0.50000 0.00000 0.00000 0.00000
0.00000 10.00000 0.50000 0.00000 0.00000
0.00000 0.00000 10.00000 0.50000 0.00000
0.00000 0.00000 0.00000 10.00000 0.50000
0.50000 0.00000 0.00000 0.00000 10.00000

3 个评论
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MUKESH KUMAR
MUKESH KUMAR 2018-1-10
if I had similar matrix A size of 994*24 then how it works , I can not relate its function.because here A size is 3*5. Thanks
Stephen23
Stephen23 2018-1-10
The code I gave you does not care what size A is. Try it.
MUKESH KUMAR
MUKESH KUMAR 2018-1-10
thanks I got it and working well

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