Matrix filling with for loop
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Hi everybody. so i'm an ultra beginner in matlab and i need your help to find a solution to the problem i have.
i'm trying to make a very simple calculations for solid state physics, it should be something like z = constant * x/y , to plot a surface graph of z, to evaluate the applicability limits of my experiment. x and y are identical vectors from 1 to 100 in steps of 1. In my mind, i think I need to build a matrix where the elements cosists in all the possible ratios between the single elements of x and y, in order to obtain my surface. I think i need to employ a for loop but i'm a bit stuck on the syntax. is there anyone that can help me? many thanks Francesco
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For loop documentation : https://fr.mathworks.com/help/matlab/ref/for.html?searchHighlight=for&s_tid=doc_srchtitle
f = zeros (100, 100) %I create the matrix that will lately be filled with the values
Correct, but you don't have to define your x vector to do the for loop.
If you want to loop over 100 element in step of one, you can write it like :
for i=1:1:100
for i=1:100
Both solution are the same because default step is 1.
But you should start to write the program you want to use, and then convert it into Matlab language.
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I don't really get hat you're are trying to do
i don't know any coding language : just write it in english, like :
Step 1 : create a matrix f of dimension (2,2)
Step 2 : for i=[1 2 3 4]
Compute z=1/i;
end for
Step 3 : Assign to the first element of f the first element of z
Bruccio
2018-1-11
Ok, it is clear now.
So, the way you initialize your matrix is ok.
f = zeros (100, 100);
what you can do, is to loop over 100 elements, for example for each row, and set each row to the desired value. Something like :
f=zeros(100,100);
for i = ... % loop over 100 elements
% i should take value 1, 2,3 ...
% then you can access ith row of f with f(:,i)
f(:,i) = ... % set the desired value for each row
% for example, your first row can be defined as
% f(:,1)=[1:100]'
end % end of for loop
f % display the result
Bruccio
2018-1-11
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