Replace numbers by strings

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wave_buoys
wave_buoys 2018-1-14
评论： Jos (10584) 2018-1-15
Hi,
I have a matrix A= 1x100, and now I want to replace if numbers in A < 90 by 'case1' and A>=90 by 'case 2'
Could anyone offer some help?
Thanks
  2 个评论
per isakson
per isakson 2018-1-14
Strings, e.g. 'case1', cannot be stored in a numerical matrix.
Stephen23
Stephen23 2018-1-14
htran's "Answer" moved here:
I mean probably I have to create a matrix B 1x100 which contains strings: 'case1' and 'case 2'. For example:
A B
10 case 1
100 case 2
40 case 1
.. so on
But I don't know how to a new matrix B according to numbers in matrix B.
More help please

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per isakson
per isakson 2018-1-14
编辑：per isakson 2018-1-14
One way:
A = randi([80,100], 1,100 ); % Sample data
C = cell(size(A));
C(A<90)={'case1'};
C(A>=90)={'case2'};
result
>> C(1:5)
ans =
'case1' 'case2' 'case2' 'case2' 'case1'
  1 个评论
Jos (10584)
Jos (10584) 2018-1-15
Great and simple answer by Per. A minor suggestion:
A = [80 90 100] % data
C = repmat({'case1'}, size(A))
C(A>=90) = {'case2'}

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更多回答（1 个）

Jan
Jan 2018-1-14
Or:
Pool = {'case1', 'case2'};
B = Pool((A < 90) + 1)
Or:
B = sprintfc('case%d', (A < 90) + 1)

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