How to get the mean of a function when the input of the function is a distribution?
1 次查看(过去 30 天)
显示 更早的评论
I want to get the expectation of y=sin(x) when x follows a distribution described below. But the second line has error. How can I fix this?
x=makedist('Uniform','Lower',0,'Upper',pi/2)
y=sin(x);
mean(y)
0 个评论
采纳的回答
Walter Roberson
2018-1-15
编辑:Walter Roberson
2018-1-15
The easiest approach is the numeric one:
>> mean(sin(random(x,1,10000)))
ans =
0.636616269663442
>> mean(sin(random(x,1,10000)))
ans =
0.636757666186139
>> mean(sin(random(x,1,10000)))
ans =
0.632276664694085
If you need the theoretical answer then rely upon the fact that you have a uniform distribution and calculate the expectation of sin(x) x from 0 to pi/2 symbolically:
syms x
int(sin(x),x,0,pi/2)/(pi/2)
Numerically this comes out as about 0.636619772367581
0 个评论
更多回答(1 个)
Torsten
2018-1-15
I think you will have to go back to the general definition of the mean of a probability distribution.
Best wishes
Torsten.
0 个评论
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!