extract numbers from string in a cell

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S
S 2012-5-8
Hi, I have a cell containing a string such as 'TT21abc.def'. I want to extract just the numbers so I'm left with '21'. Does anyone know how? I tried using sscanf but I was getting errors and think I don't have the right format inputs. Thanks in advance.

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采纳的回答

Friedrich
Friedrich 2012-5-8
Hi,
you can use regexprep or some ascii value representation comparison to do so, e.g.
a = {'TT21abc.def'};
%ascii value comparison, char(48) = '0' and char(57) = '9'
a{1}(a{1} <= 57 & a{1} >= 48)
%or use regexprep
regexprep(a{1},'\D','')
If you have a cell array with strings, I would use regexprep because it can handle cell arrays of strings as input
b = {'TT21abc.def'
'sdfsdf34435afafsd.,.,3434'}
out = regexprep(b,'\D','')

更多回答（1 个）

Andrei Bobrov
Andrei Bobrov 2012-5-8
with using function regexp
regexp(a,'\d*','match')
or:
b = {'TT21abc.def'
'sdfsdf34435afafsd.,.,3434'}
out = regexp(b,'\d*','match');
out = cat(2,out{:})

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