interpolating Sample data to finer increment

Question

Michael 2018-1-16

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https://ww2.mathworks.cn/matlabcentral/answers/377471-interpolating-sample-data-to-finer-increment

评论： Thorsten 2018-1-18

采纳的回答： Thorsten

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Hello,

What I have is a 3D set of point X, Y and Z(Weights) and I want to be able to interpolate the Z data to finer intervals in the X and Y direction. Say X from -17.5, 17.5 in 0.5 steps and Y 15 to -15 in 0.25 step.

------- Zone -17.5 0 17.5 15 0.6 0.8 0.6 0 0.7 1 0.7 15 0.6 0.8 0.6 -------

[Weights] = [0.6 0.8 0.6; 0.7 1.0 0.7; 0.6 0.8 0.6];
[X] = [-17.5,0,17.5];
[Y] = [-15, 0, 15];
figure
surf(X,Y,Weights)
title('Original Sampling');

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Answer 1

Thorsten 2018-1-17

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https://ww2.mathworks.cn/matlabcentral/answers/377471-interpolating-sample-data-to-finer-increment#answer_300548

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Vq = interp2(X,Y',Weights, -17.5:0.5:17.5, (-15:0.25:15)');

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Answer 2

Michael 2018-1-17

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https://ww2.mathworks.cn/matlabcentral/answers/377471-interpolating-sample-data-to-finer-increment#answer_300549

Thanks

Both of the following lines did solve my issue; however, I am not sure what the ' does, In this example exactly what does the prime symbol ' achieve?

Vq = interp2(X,Y,Weights, -17.5:0.5:17.5, (-15:0.25:15)', 'cubic'); Vq = interp2(X,Y,Weights', -17.5:0.5:17.5, (-15:0.25:15)', 'cubic');

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Thorsten 2018-1-18

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The ' transposes the vector from a row to a column vector. From the help of interp2:

Xq can be a row vector, in which case it specifies a matrix with
constant columns. Similarly, Yq can be a column vector and it
specifies a matrix with constant rows.

Not that if you transpose your Weights you will have a different solution.

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