Removing rows of a matrix based on rows of another matrix!

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Antonio
Antonio 2018-1-17
回答： Steven Lord 2018-1-17
Imagine I have two matrices with different sizes (let's say 6x2 and 5x2) as follows:
A = [47 10;
29 10;
23 10;
34 10;
12 10;
64 10];
B = [23 20;
12 20;
54 20
47 20;
31 20];
I need to compare A(:,1) with B(:,1) and delete the rows in matrix A whose first-column-element is different from matrix B's first-column-element (so my focus is only on first columns of the matrices). So I should eventually get something like this:
A = [47 10;
12 10;
23 10];
as "47", "12", and "23" are the only first-column-elements in A that also exist in B! I have written this but I get the error "Matrix dimensions must agree."!
TF = A(:,1) ~= B(:,1);
A(TF,:) = [];
Any ideas how I could fix this?

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采纳的回答

Birdman
Birdman 2018-1-17
A=A(ismember(A(:,1),B(:,1)),:)

更多回答（1 个）

Steven Lord
Steven Lord 2018-1-17
Since it doesn't seem like ordering matters [you don't require A(n, 1) to match B(n, 1) as long as it matches some element in B(:, 1)] use the ismember function.

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