Part of this question has nothing to do with tables, the other part does:
1) Not sure how 50 comes from Forest,B, but let's assume you have a desired value for every possibility in the 3x3 set of combinations. You can make a matrix, and use sub2ind to get the right elements for each actual combination.
2) If your table is called t, and your function is called fun, a simple assignment using dot subscripting will create a new variable.
Consider using a table, and categorical variables for LandCover and SoilType. Put all that together, and it looks like this:
>> LandCover = categorical([1;2;3;1;2;3],1:3,{'Forest' 'Urban' 'Vegetation'});
>> SoilType = categorical([1;1;2;2;3;3],1:3,{'A' 'B' 'C'});
>> t = table(LandCover,SoilType)
t =
6×2 table
LandCover SoilType
__________ ________
Forest A
Urban A
Vegetation B
Forest B
Urban C
Vegetation C
>> t.Value = fun(t.LandCover,t.SoilType)
t =
6×3 table
LandCover SoilType Value
__________ ________ _____
Forest A 1
Urban A 4
Vegetation B 8
Forest B 50
Urban C 75
Vegetation C 9
with
function v = fun(lc,st)
values = [1 50 3; 4 5 75; 7 8 9];
i = sub2ind([3 3],double(lc),double(st));
v = values(i);
