system response

6 次查看(过去 30 天)
shalipse
shalipse 2012-5-8
Hi everyone, i am trying to obtain a response of a first order system to a step input, however the output the graph depicts doesn't match with what i expected. would someone be kind enough to give me a push in the right direction. the script for the program is thus:
clear all clc k1 = 2e4; k2 = 2e7; k3 = 2e4; c = 2e10; num= [(k1*c) (k1*k2)]; den= [(c*k1*k3) (k1*k2*k3)]; P=tf(num,den); display (P) step (P), grid title('y3 with a step input') %ylim([0 1])
Regards

采纳的回答

Arkadiy Turevskiy
Your system P, as defined, is simply a gain. You can see that if you do
zpk(P)
ans =
5e-05 (s+0.001)
---------------
(s+0.001)
You can even see it if you look carefully at your num and den formulas:
num = k1*c*s+k1*k2 =k1*(c*s+k2)
den = c*k1*k3*s+k1*k2*k3 = k1*k3*(c*s+k2)
Therefore
num/den = k1* (c*s+k2) / (k1*k3* (c*s+k2)) = 1/k3
This is exactly what you see when you look at step response.
In short, recheck your formulas.
Arkadiy
  2 个评论
shalipse
shalipse 2012-5-8
Thank you Arkadiy for providing me with a good hint. but does this implies that the system is unstable? and what further analysis can be made to the system?.
kind regards
Arkadiy Turevskiy
the system is simply a gain, so it is stable. You need to recheck your formulas, most likely there is an error in how you calculate num and den.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Time and Frequency Domain Analysis 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by